Instruments For Testing Your Innovations
Electromagnetic coils such as relays, solenoids, inductors, Helmholtz coils, electromagnets, and electric motors often time required high-
Figure 2. Waveform amplifier drives high current through the coil at resonance.
At high frequency on the other hand, the impedance of a coil or inductor increases with frequency. Z = jL. At high frequency the coil impedance is very high such that high voltage is needed to drive high current through the solenoid coil. For example, at 200kHz the impedance of a 2mH electromagnet will be 2512 ohm. If you drive the electromagnetic coil with 40V for example, you would get about 16mA (40V/2512 ohm = 16mA). For most applications, this is not enough current to produce enough magnetic field. For high magnetic field applications, higher current through the coil is desired. To drive a 1A high-
Figure 3. At resonance the inductor and capacitor impedance cancel each other and act like a short circuit.
To operate the coil in resonance mode, a series capacitor is added as shown in Figure 2. The series capacitor impedance has an opposite polarity than the inductance. Thus the capacitor is acting as an impedance cancellation device. It reduces the total impedance. At resonance the capacitor reactance (imaginary portion of the impedance) is completely cancels the inductor reactance. That is the inductor and capacitor reactance are equal magnitude but opposite polarity. Only the inductor’s parasitic resistance remained. With only resistance remained, the waveform amplifier can drive high-
To further understand impedance cancellation at resonance, consider Figure 3 using 2mH solenoid and 200kHz. At resonance the voltage across the capacitor is -
Figure 1. Waveform amplifier directly drives an inductor coil with a parasitic resistor.
To achieve high-
Choose the series capacitor with capacitance such that the capacitor reactance is the same as coil reactance at a given resonant frequency.
Using the above example for 2mH Helmholtz coils and 200kHz operation, the series capacitance is calculated 317pF. The capacitor should be high-
I is the peak current.
Using the above example, the voltage rating must be at least 2.5kV (V = 1A * 2512ohm = 2512V). Add additional voltage rating margin in case higher current is used.
High voltage capacitors can be found in the below websites:
If you have the ability to choose your own relay coil or design your own coil, consider the follow criteria.
o Low resistance to reduce heating and allows higher current
o Consider resistance increases at high frequency due to skin-
Related App Notes
PDF Version of this App Note
Coils and Inductors
Solenoids and Relays
Electromagnets and Motors
Scientific and industrial testing
Driving magnetic coil